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The Horizon Quantum of Area

  Several independent semiclassical arguments converge on $$\boxed{\Delta A=8\pi l_{\mathrm{Pl}}^2}, \qquad l_{\mathrm{Pl}}^2=\frac{G\hbar}{c^3}$$ I got interested in this reading the 2018 paper  Bekenstein, I, and the quantum of black-hole surface area . Even though I disagree with Hod, its a great paper.  Honourable mentions also go to:   The Physical Interpretation of the Spectrum of Black Hole Quasinormal Modes , 2008  The Off-Shell Black Hole , 1994     On Black Hole Spectroscopy via Adiabatic Invariance , 2012 An Analytical Computation of Asymptotic Schwarzschild Quasinormal Frequencies , 2003  Asymptotic Black Hole Quasinormal Frequencies , 2003  1. Horizon Action Near any nonextremal horizon, imaginary time turns the normal geometry into a plane: $$ds_E^2\simeq d\rho^2+\rho^2d\Theta^2+\cdots.$$ Smoothness requires one horizon cycle: $$\oint d\Theta=2\pi.$$ The gravitational action identifies the momentum conjugate to $\The...

Zitter at the Edge of Spacetime

 In a previous post we introduced the idea that our current Universe has boundary conditions. 
 
We also showed a diagram similar to Figure 1 below. Except here, we are once again thinking about the future dS state.

Figure 1. For an observer at O inside the cosmic event horizon (CEH) with radius $l_{\Lambda}$, the universe can be divided into two sub-vacuums, $(A)$ inside the CEH, and $(B)$, outside. The horizon surface $\Sigma$ has entanglement entropy $S_{dS}$ and rest energy $E_H$

 
Figure 2. The maximum entropy of the Universe (credit: Lineweaver).  

Now, a comoving volume of the Universe, when considered together with its associated cosmic event horizon, forms a thermodynamically closed system obeying the generalised second law, $$dS_{\text{bulk}} + dS_{\text{horizon}} \ge 0.$$ The maximum entropy of a closed system, in this case  (Figure 2) with $L=2 \pi l_{\Lambda}$, the circumference of a circle with radius  $l_{\Lambda}$,  is obtained when total $E_{H}$ is worked, i.e. degraded into the smallest bits possible. All energy is converted into minimal energy dark photons with wavelengths as large as the system $L$. Because the relevant thermodynamics and quantum degrees of freedom are governed by the Holographic Principle, these physical modes do not propagate through the 3D bulk; they are strictly confined to the 2D $S^2$ horizon surface. Consequently, the maximal fundamental wavelength is bounded not by the bulk diameter, but by the topological great circle of the boundary: $\lambda_{max} = 2\pi l_\Lambda$. From the Compton wavelength relation, the minimum quanta of energy $E_{s}$ of this system is then: \begin{equation}
\notag
E_{s}=\frac{hc}{\lambda_{max}}=\frac{\hslash c}{l_{\Lambda}}=m_{s}c^2
\end{equation}

This defines $m_s$ (discussed in a previous post) as the irreducible mass gap of the holographic surface. Within this framework, $m_s = \hbar / (rc)$ acts as a universal spectral mass function linked by UV/IR duality ($r \leftrightarrow 2L_P l_\Lambda / r$). It resolves to $M_P / 2$ at the UV boundary ($r = 2L_P$) and $\hbar / (cl_\Lambda)$ at the IR boundary ($r = l_\Lambda$).  In 2014, Barrow and Gibbons confirmed this lower-bound analysis and also pointed out that there is classical upper bound (note that their paper has a factor-of-two error in the upper bound) for any mass in a Universe with a positive cosmological constant. We can see this upper bound is actually equivalent to $m_{CEH}$,  the mass of the cosmic event horizon of our Figure 1 system:   \begin{equation}m_{upper} \leq \frac{c^{2}}{2G}\sqrt{\frac{3}{\Lambda }} =\frac{c^2 l_{\Lambda}}{2G}=  m_{CEH} 
\end{equation}  
We know from cosmological observations that $m_{CEH}$ is the observed (effective) mass of the CEH. 

Now, quantum field theory can be formulated in terms of harmonic oscillators. So, if we consider our Figure 1 system as a quantum harmonic oscillatorwith $E_s = m_s c^2$ as the ground state (zero-point) energy and  $\omega_{s}$ being the ground state angular frequency.    
\begin{equation}
\notag
E_{s}=\hslash \frac{\omega_{s}}{2}
\end{equation}
  Now, the de Broglie relation is then:
\begin{equation}
\notag
E_{s}=\hslash \omega_{B}
\end{equation} Of course, these are not the same $\omega$ unless we compare internal vs. external clock rates (exactly what happens in zitterbwegung). Because the fundamental modes are confined to the $S^2$ boundary, their evolution is not merely a scalar translation but is generated by spatial rotors (bivectors) in geometric algebra ($C\ell_{3,0}$). 

Wait, I hear some of you saying, $H_0$ is usually presented as (km/s/Mpa) rather than ($s^{-1}$),  and you are right, but that simply due to cosmologists confusing things, using more convenient units 

Anyhow, if we model the vacuum state at this boundary not as a naive 3D bosonic oscillator, but as a field of spatial rotors, the zero-point ground state energy remains $E_s$. As  $\omega_{s}=2\omega_{B}$ we might consider $\omega_{s}$ as the zitter frequency of vacuum. Things get even more interesting when we realise that  $\omega_{B} = c/l_{\Lambda} =H$ implying that the Hubble Constant can be considered as a `de Broglie'  (or effective) frequency of vacuum; or equivalently, as per Chappell et al, 2016, Time as a Geometric Property of Space. That is, the macroscopic value $H = c / l_\Lambda$ is the irreversible scalar component ($t$) of the universe's evolution, while the vacuum frequency $\omega_s = 2H$ is the bivector component ($jn$). Thus, the universe's expansion is not just scalar; it possesses an intrinsic quaternionic rotation at the boundary, reconciling the bosonic geometry of macroscopic expansion with the fermionic Zitterbewegung of the quantum vacuum. This also all implies the horizon vacuum is a something like a highly degenerate spin liquid, a macroscopic condensate of phase-synchronised spatial rotors bounded at the IR cutoff.   

  

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